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yeast competitive factors

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JLem

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A couple of questions regarding yeast competitive/killer factor. I know this doesn't apply to yeast usually used in beer (as none of them are "killers"), but after listening to an archived podcast on the BN (the one with Shea Comfort), I am interested in using some wine yeasts for some beers. I originally posted these questions in the wine forum, the only response I got was to try this forum. Maybe someone here can help?

1) What happens when two (or more) killer yeast are used together? Are they intrinsically immune? will they kill each other off? will one out-compete the other(s)?

2) How is Brettanomyces affected by kill factors? Are they susceptible? What about bacteria like Pediococcus and Lactobacillus?
 
Sorry to hop on an old thread, but I'm curious about something along these lines as well. I'm interested in taking unpasteurized and unfiltered cider and adding yeast without any pasteurization or chemical additives. I'm not sure how practical this is or if there is a particular strain of yeast that would be best suited for an attempt. Again, this isn't something I'm attempting yet. I'm just curious if it's possible or just a disaster waiting to happen.
 
Science knows at least 6 killer factors in S. cerevisiae, but as far as I can learn, at most 3 of them are expressed by commercially available wine yeasts: K1, K2, and K28.

A yeast that secretes a killer factor (or competitive factor, or zymocin ... terminology is really unsettled here) is also immune to it, so 2 strains that secrete the same one are presumably back to competing on other grounds -- speed of reproduction, tolerance for alcohol. But 2 strains that secrete different killer factors are both going to have a rough time of it.

K1, K2, and K28 only kill within the Saccharomyces genus. Klus kills in some other yeast genera. None of them kill Brettanomyces.
 
And for the reasons you mentioned, one will almost always win out. How long that takes to happen also depends on these factors. So if you mix two strains, it's not like you have an indefinite ratio.
 
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