Is this the right way to figure out ABV when diluting?
I know I will have to sulfite, sorbate and force carb, and this may not be the sweetening dilution percentage used. But I found that sweetening with juice taste a lot better than sweetening with concentrate. I just want to have an idea how much ABV is in my final product.
Lets say I have a 5 gallon (640 oz.) batch of cider with OG of 1.062 and FG of .996, the ABV would be 8.646%.
Calculation --> (1.062 - .996) * 131 = 8.646
8.646% of 5 gallons (640 oz.) is 55.3344 oz. of pure alcohol.
Calculation --> 640 * .08646 = 55.3344
If I sweeten with 1 gallon (128 oz.) apple juice to make a total of 6 gallons (768 oz.) the pure alcohol would still be 55.3344 oz., making the ABV 7.205%.
Calculation --> 55.3344 / 768 = 7.205
Is this correct?
I know I will have to sulfite, sorbate and force carb, and this may not be the sweetening dilution percentage used. But I found that sweetening with juice taste a lot better than sweetening with concentrate. I just want to have an idea how much ABV is in my final product.
Lets say I have a 5 gallon (640 oz.) batch of cider with OG of 1.062 and FG of .996, the ABV would be 8.646%.
Calculation --> (1.062 - .996) * 131 = 8.646
8.646% of 5 gallons (640 oz.) is 55.3344 oz. of pure alcohol.
Calculation --> 640 * .08646 = 55.3344
If I sweeten with 1 gallon (128 oz.) apple juice to make a total of 6 gallons (768 oz.) the pure alcohol would still be 55.3344 oz., making the ABV 7.205%.
Calculation --> 55.3344 / 768 = 7.205
Is this correct?