Just what I figured, just because. But you also don't mention your brewing size. The reason I brought this up in the first place is in reality the cost of the element has little to do with it. It is the cost of the power that concerns me. In transitioning to a 3bbl setup the cost of power actually becomes a substantial fixed cost. This is what sparked my interest. I still think the issue is more want than need.
After capital costs, it's cheaper to change temperature faster, with a more powerful element, than it is to go slower.
The amount of heat energy required to change the temperature of the water/wort is fixed by the volume and the temperature change, and doesn't depend on time taken to change temperatures. However, the total heat energy lost from the kettle during the heating phase is at least proportional to the temperature difference between the water and surroundings multiplied by the time taken (actually it increases a little bit faster than the temperature difference). The longer you take to change temperature, e.g. from mash out to boil, the more total heat losses you have to overcome, and the more energy you have to use.
You can see this from the extreme case, where you supply only a tiny bit more power than your heat losses in order to heat your wort. If at mash out temps in your kettle, you are losing 100W of heat, and you supply 101W of power to the element, then the heat energy in the wort will only rise by 1 J/second. If you supply 1100W of power, the heat energy in the wort will rise at 1000 J/second, and you'll reach 1000 J more heat energy in the wort 1000 times faster than the first case, losing 99.9 kJ less to kettle heat losses.
Calculating it for the full temperature change is more complex, because heat losses aren't constant, but a function of temperature.
For direct flame heating, it can be much more complex, as the efficiency of transferring heat from the fuel to the wort isn't fixed. For immersed electrical elements though you can pretty much treat them as having a constant efficiency.