restive loads like a heater don't work this way, power output drops as voltage drops. assuming element rated 1800 watts at 120 volts, looking at something a bit over 1500 watts output at 110 volts or around 13.75 amps.
Correct. If P = power in watts, I = current in amps, V = voltage, and R = resistance in ohms, then the following describe the relationships among the values:
V = I * R
I = V / R
R = V / I
P = I * V
P = I^2 * R
P = V^2 / R
R = V^2 / P
The two bold formulas can be combined and/or rearranged to give the others.
A heating element is a fixed value resistor. An element rated at 1800W @ 120V, means that it will produce 1800W
if the applied voltage is 120V. The resistance of such an element is:
R = V^2 / P = 120^2 / 1800 = 8.00 ohms
This resistance will not change as the applied voltage changes, but the power (and the current draw) will. Power at various input voltages will be:
P @ 120 V = 120^2 / 8.00 = 1800 W
P @ 115 V = 115^2 / 8.00 = 1653 W
P @ 110 V = 110^2 / 8.00 = 1513 W
P @ 105 V = 105^2 / 8.00 = 1378 W
The currents drawn at different input voltages will be:
I @ 120 V = 120 / 8.00 = 15.00 A
I @ 115 V = 115 / 8.00 = 14.38 A
I @ 110 V = 110 / 8.00 = 13.75 A
I @ 105 V = 105 / 8.00 = 13.13 A
Brew on
Edit: Correct last four formulas as they are for current (I), not voltage (V).