How much does water (wort specifically) expand or contract as it is heated to a boil or cooled after flameout? What is the formula?
Volume as a function of temperature?
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Start here,
http://en.wikipedia.org/wiki/Thermal_expansion
The number I've always heard is that water (and wort??) expands 4% of volume between room temp and boiling.
http://en.wikipedia.org/wiki/Thermal_expansion
The number I've always heard is that water (and wort??) expands 4% of volume between room temp and boiling.
OP
OP
So then, basically, 5.75 gallons of boiling wort will cool to 5.5 gallons at pitching
Thereabouts. That's what Beersmith calculates for my 5.75 gallon batches. I could dust off my Differential Equations textbook, but...nope.
pricelessbrewing
Brewer's Friend Software Manager
I used the engineers toolbox for thermal expansion of water. Roughly 2.2% at mash/strike temps, and 4.4% at boil.
I'll provide the 3rd poly equation I fit to it when I get home in a half hour.
I'll provide the 3rd poly equation I fit to it when I get home in a half hour.
OP
OP
I really appreciate the link as well as the "shoot from the hip" info. Guess I could've looked it up myself, but thank you! It seemed I was losing about that much, and I looked at the link and read through it and got lost pretty quick.. Amazing what you lose over time
I think 99.9% of the quarter gallon is lost due to evaporation
pricelessbrewing
Brewer's Friend Software Manager
m00ps, that's just plan wrong. If you take a volume of water and cool it, there's basically no evaporation going on there. It's just the molecules are less energetic so they take up less space (simplified version). If you want to know the ramifications, look up the guy that did a no chill in a stainless steel kettle and clamped the lid on with a gasket. Here's a spoiler, it dented the crap out of the kettle.
Fourth poly is Volume multiplier = = 0.000000t4 - 0.000000t3 + 0.000002t2 - 0.000158t + 1.002659
You can get a really good approximation with just 0.000001 (t^2) - 0.000021(t) + 0.998528. Where t is the temp in degrees F.
Of note:
at 140F V=1.0173
149F V=1.0204
158 1.0225
167 1.0256
212 1.01438
Fourth poly is Volume multiplier = = 0.000000t4 - 0.000000t3 + 0.000002t2 - 0.000158t + 1.002659
You can get a really good approximation with just 0.000001 (t^2) - 0.000021(t) + 0.998528. Where t is the temp in degrees F.
Of note:
at 140F V=1.0173
149F V=1.0204
158 1.0225
167 1.0256
212 1.01438
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