471123581347
It's obvious that is is not what Dan (is it Dan Brown?) has in mind but this Figlio di Bonnaccio thinks you have to give credit for this answer.
471123581347
1
11
21
1211
111221
I may misunderstand your answer, and if so please forgive.
This one is base ten, sure as I live.
As one further clue, I'll concede the next line
Of the sequence I started. Guess the next - is that fine?
312211
So what's next, do you think?
I say the numbers, with a wink.
Not likelyThere is a party of 100 high-powered politicians. All of them are either honest or liars. You walk in knowing two things:
- At least one of them is honest.
- If you take any two politicians, at least one of them is a liar.
From this information, can you know how many are liars and how many are honest? and if you can, how?
Not likely
If there are n liars the probability that a randomly selected politician is truthfull is (100 - n)/100. The probability that a second selected politician is also truthful is (99 - n)/99. Given that the two selections are independent the probability that both are truthful is (100 - n)*(99 - n)/(100*99). As at least one is always a liar the probability of this event is 0. Thus (100 - n)*(99 - n) = 0 which is satisfied if n = 99 or 100. But we know (though we are skeptical) that at least one is honest and that knocks out n = 100 as the acceptable solution.
Classic 'sampling without replacement' problem.
We really need to stop doing math problems with Ajdelange about
Your up next if there was any doubt
AJ has a mind decidedly stout
With numbers and math, some of us get lost at no doubt
I hope I don't sound like a bad token.
AJ is to this thread is a golden spiral spoken
Let me help the man, who flattered me as Dan Brown
It was a very nice complement spoken to my Dasher Brown.
Here is one from way back when
I don't remember if I ansewered it .. could have left me stipend (it rhymed - sort of).
If I may, this one come’s from a Passedpawn play
I was actually looking for something else on this day
Although the good PP plays it down
His mind is sharp and his wit's astound
I gotta say the Marine in him
Wins, and wins.. in my heart I happily grin
He is something else. But will never let on. No need to prove himself.
From the PP treasurer box.. (sorry Pappy, can't help but exploit you occasionally )
Molly was a brewer's wife, as faithful as the sun,
Brewer Bob, an abusive man, was Molly's mean husband.
Brewer Bob used black clay jugs to measure his brewing water,
and Bob demanded precision during mash and boil and lauter.
One day Bob sent poor Molly to the well across the moor,
"Lower down these jugs, my wife, and bring back exactly four."
Four gallons seemed a simple task, and Molly left with glee,
until she saw the jugs she took held exactly five and three.
5 gallons rich holds one jug, the other 3 gallons poor,
How will Molly return to Bob with exactly four?
Fill the 3 gallon and pour into the 5, fill the 3 again and pour I to the 5 til its full. Dump the 5 and pour the remaining gallon from the 3 into the 5 and fill the 3 one last time, pour into the 5 to make 4 gallons.
There is now 1,589 post in this thread and I'm foolishly going to ask the same first question, possibly different wording-- but the same question as the first post.
9 balls that each look exactly the same
One weighs different from the others... Heavier or lighter it does not matter
You have a balancing scale. Think of the pictures often used for The Hall of Justice scale
I'll give you a hint. You can put four and four on the scale . It's not going to get you the answer. There are to many vaiables with that idea.. Just know it only takes two measuring's to answer the question.
This riddle is decided in two moves. Every time .
I've heard a variation on this one but not sure if you guys have posted it yet so sorry if that's the case.
Same concept but you have to identify if the odd ball is heavier or lighter. You have 12 balls and
3 uses of the scale.
I've heard a variation on this one but not sure if you guys have posted it yet so sorry if that's the case.
Same concept but you have to identify if the odd ball is heavier or lighter. You have 12 balls and 3 uses of the scale.
Oops I was in the can
takes only two tries to answer my man
this question could vey well be my bastard hour
Nobody made me work so hard in the answer I devour
You, Sideways, I respect you for trying
But three weighing's? In that I'm not buying
.
I'll guess at a water/alcohol solution. The more water is removed (the drier the solution becomes) the better wetting agent it is.
I believe the answer is a towel. As you dry things with it, it gets wetter.
Or gets wetter as it dries.
Sent from somewhere to someone
I've heard a variation on this one but not sure if you guys have posted it yet so sorry if that's the case.
Same concept but you have to identify if the odd ball is heavier or lighter. You have 12 balls and 3 uses of the scale.
You must have been looking at the object on the back of my bathroom door,
that is exactly the answer I was looking for.
Now, if you havent already you will soon learn,
the prize for a correct answer is that it is your turn.
I will do my best to carry on. I am no artist of rhyme or song. I'll attempt to clear the cobwebs from my brain and pose this riddle for those who wish to see. Can anyone find the answer within range? "Smell me, buy me, and deliver me.
I won't change."
What am I?
You won't change, but I was given some change for a drink
And then you were there, I think
Then I dropped you while holding my cup
A day of good luck to whoever picks you up
You won't change, but I was given some change for a drink
And then you were there, I think
Then I dropped you while holding my cup
A day of good luck to whoever picks you up
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