If we remove the other variables involved and just make a mash with artificially mineralized water and a known malt, we have to assume the pH shift comes from one or the other.
Let me run some analysis quick to try and illustrate this.
Okay. Let's try a few things out:
Let's use my "European Pilsner" malt class as I think it is the least suspect, or "garbage", with respect to it's titration values and pH DI. We'll use 32 l as our water volume, 5.67 kg of malt, and 5.4 as out pH target (pHz). I'll run it with the linear equivalent equation because it does not hurt much to do so (we know linear is a decent fit for this type of malt):
European Pilsner (mEq/kg) = a1 * (pHz - pH DI)
European Pilsner (mEq/kg) = -34.40 * (5.4 - 5.84)
European Pilsner (mEq/kg) = 15.14
European Pilsner (mEq) = 85.82
Grist pH = 5.838
Now let's add enough Gypsum to hit 100 mg/l in the strike water, which turns out to be ~ 13.7 g. Using Kolbach's value of 3.5, we drive pHz to:
pHz = 5.605
Let's assume we actually did perform this and measured a pHz of 5.63. Let's use A.J.'s "back of the napkin" estimate of 50% of the nominal Kolbach for the mash and change the denominator in our calcs to 7:
pHz = 5.721, Δ (to 5.63)= 0.09
That Δ now has to come from somewhere in order for us to rectify it. Since we have no other constituent parts, we have to assume it means we modeled the malt incorrectly. With the linear equation, we only have 2 levers to pull:
pH DI and a1.
In order to hit pHz = 5.63, we'd need to drop the pH DI to 5.75, which while not unreasonable in the slightest, would go against the maltsters value of 5.84, which if anything, considering the unknowns involved, is the most trustworthy of the "garbage" data we have. How about a1? We'd have to drop that to -20 to hit 5.63. I did not titrate this malt so I cannot speak to whether this is practical, but we have only doubled the Kolbach denominator at this point.
Let's triple it (10.5), which means we are still not at the proposed Pilsner malt denominator from the paper.
pHz = 5.76, Δ (to 5.63)= 0.13
In this case, pH DI and a1 would have to drop to 5.71 and -13 respectively. We are starting to get a bit squirrelly here. Now let's move the denominator to the value from the Barth and Zaman paper:
pHz = 5.783, Δ (to 5.63)= 0.15
In this case, pH DI and a1 would have to drop to 5.69 and -9.5 respectively. We are not in realistic territory anymore, IMHO.
Obviously, I made 2 very big assumptions here: 1.) the measured pHz and 2.) the data for the Pilsner, but I mostly wanted to illustrate that if you isolate things to a few variables, you would have to make tweaks to the malt that may be unreasonable to justify the Barth and Zaman paper.