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Recipe parameters reversal engineering

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nexy_sm

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Hi all homebrewers,

I would like to consult you all about something. Namely, I am able to buy kit for making 10 L of APA.
The specification is following:
Batch volume 10 L,
SG = 1.050

The kit contains following malts:
1.2 kg pale ale malt
0.4 kg cara ruby
0.4 kg wheat blanc
0.125 kg cara gold

Since they suggest more or less primitive way of sparging, as a simple rinsing of the rest of the trub with the hot water, and I am going to use coller as a mash tun, I would like to see what can I expect from this recipe, and since it is already homebrewing recipe, equations for adopting standard recipes can't be used. Finally i would like to know how much water should be in the mash tun before first runoff if I use no-sparge method.

Is it enough to do the following:
1. calculate potential of the malt in the tun (points at the end)
2. estimate no sparge efficiency to 65% as palmer says
3. calculate batch volume based on efficiency, total points and wanted final gravity.
4. estimate boil off and add adequate volume of water to make it for boilling.


or it should be done in this way (based on ken schwartz's equations):
1. estimate boil off volume and adjust boil gravity, BG
2. estimate grain absorption rate, Ra
3. based on Ken's equation, number of collected points in the running is P=Pa(1-Ra/R1), where R is mash thickness.
BG = P/Vm => P = BG*Vm
Since R = Vm/Wg (volume of water in the mash tune divided by weight of the grain).
From equation for P we get quadratic equation for Vm with known parameters like absorption rate and number of available points for continious sparge, Pa, which I would calculate as 80% efficiency of maximum potentinal, but I am not sure if it should be done like that and what is the usual number)
When solving quadratic equation for Vm I expect to get one positive and one negative solution but also I'll see. Anyway i will drop the worse.
When I know Vm, everything is clear.

Hope this will not be hard to follow.

Cheers
 
I sort of lost you about halfway through there, but the math you're trying to do isn't actually all that hard (especially if you use software):

1ppg = 8.35 points/kilo/liter

1.2 kg pale ale malt = 1.2kg * 37points/pound/gallon = 1.2kg * 308.8 points/kilo/liter = 370 points/liter
0.4 kg cararuby malt = 0.4kg * 35ppg = 0.4kg * 292.25 points/kilo/liter = 117 points/liter
0.4 kg white wheat malt = .4kg * 37ppg = 0.4kg * 308.8 points/kilo/liter = 124 points/liter
0.125 kg cara gold malt = .125kg * 35ppg = .125kg * 292.25 points/kilo/liter = 37 points/liter
-------------------------------------------
total = 648 points/liter at 100% efficiency, or 421 points/liter at 65% efficiency = 10L of 1.042 wort
 
Actually yes, my questin should have been is using 65 % efficiency for no-sparge convenient enough?
 
Actually yes, my questin should have been is using 65 % efficiency for no-sparge convenient enough?

Hmm…I'm not sure I understand what you mean by enough. If you make 10L with this grist bill and get 65% efficiency, by my math you'll have a 1.042 OG wort. That's a bit lower than the recipe target, if that's what you're asking.
 
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