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Do I have a bigger electrical problem?

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For years my friends had problems with appliances. They always had problems with their oven, no one could fix it. Just a bunch of weird stuff going on.

One day they had some work getting done and the worker realized that wires were loose somewhere between the service drop and the fuse panel. Got it tightened up and their oven started working and all their electrical problems disappeared.

FWIW, I use a Mash & Boil with a steam slayer and get a rolling boil.
 
From the info you provided, to me, I'm not seeing any obvious sign of electrical issue.

17A @ 121V is roughly 2060W. That's not quite the 2250 listed for the coil (-8%) but with measurement tolerances and all it's not way out of line.

To account for all voltage drop through the system you'd have to measure the operating voltage at the element terminals. Don't know how feasible that is.

From what I see/read I opine it would be waste of time to haul the system elsewhere to try a different circuit.
That 2060W is what's being dissipated over the whole circuit, not just in the heater coil.

W=V×I
and W = I × I ×R
and W = VxV /R or resistance R in ohms (Ω) is equal to the squared voltage V in volts (V) divided by the power P in watts (W)

So 2250W (120V) coil would have resistance of 120×120/2250 = 6.4 Ohm
At your current of 17A
Power in 6.4 Ohm with 17A current, is 17 × 17 × 6.4 = 1850W
 
That 2060W is what's being dissipated over the whole circuit, not just in the heater coil.

W=V×I
and W = I × I ×R
and W = VxV /R or resistance R in ohms (Ω) is equal to the squared voltage V in volts (V) divided by the power P in watts (W)

So 2250W (120V) coil would have resistance of 120×120/2250 = 6.4 Ohm
At your current of 17A
Power in 6.4 Ohm with 17A current, is 17 × 17 × 6.4 = 1850W

You might have, by now, seen that was covered in post #13 more than a year ago.
 

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