promontory
Well-Known Member
I saw other threads but I am having a tough time figuring this out.
Initial Infusion Equation:
Strike Water Temperature Tw = (.2/r)(T2 - T1) + T2
where:
r = The ratio of water to grain in quarts per pound.
11.875 lbs of grain (divided by) 3.7 gal (1.25 gt per lb) = .31
T1 = The initial temperature (¡F) of the mash.
60'
T2 = The target temperature (¡F) of the mash.
165'
Tw = The actual temperature (¡F) of the infusion water.
So: (.2 / .31 = .64)(165 -60 = 105) + 165
So: .64 x 105 +165
So: 67.5 +165 = 200+... That can't be right... What am I doing wrong???
Initial Infusion Equation:
Strike Water Temperature Tw = (.2/r)(T2 - T1) + T2
where:
r = The ratio of water to grain in quarts per pound.
11.875 lbs of grain (divided by) 3.7 gal (1.25 gt per lb) = .31
T1 = The initial temperature (¡F) of the mash.
60'
T2 = The target temperature (¡F) of the mash.
165'
Tw = The actual temperature (¡F) of the infusion water.
So: (.2 / .31 = .64)(165 -60 = 105) + 165
So: .64 x 105 +165
So: 67.5 +165 = 200+... That can't be right... What am I doing wrong???