digdan
Well-Known Member
I have a corney keg that I've drank quite a bit from. I'm going to bottle the rest but I need to know how many bottles/caps to santize and get ready.
I would think its simple math, maybe simpler than this.
The tare weight of my keg is 8lbs
when the keg was full it weighed 49lbs
The keg now weighs 23lbs
I need to subtract the tare weight from both the full kegs weight and the none-full kegs weight
liquid net weight = (full keg weigh total - keg tare weight) or (49 - 8)
wich is 41
Now for the not full weight. which is 23lbs - 8lbs(tare weight) = 15lbs
to get the % of weight left its simply (not full weight / full weight) or 15 divided by 41, which is 0.365 or roughly 37% of the liquid is left.
Now lets work in ounces. How many ounces are in my full five gallon corney keg? 128 ounces per gallon would make it (5 * 128) = 640 fl ounces.
if 100% = 640 ounces. Then 37% should be around 237 fl ounces.
237 fl ounces, each of my bottles being 12fl ounces would mean I would need around 20 bottles...
Is this correct, or does CO2 have significant weight that I should be calculating?
I don't have to be dead on, since I ussually clean more bottles and caps just incase I run into a problem, or get clumsey and drop a couple.
Also is there a simpler way to measure fluid ounces of beer on a weight scale? I noticed in this calculation I have 16.5fl ounces per pound. Or does beer variety change the actually weight per volume of beer, I could see how high alcohol beers would weigh less than low alcohol beers?
Thx
I would think its simple math, maybe simpler than this.
The tare weight of my keg is 8lbs
when the keg was full it weighed 49lbs
The keg now weighs 23lbs
I need to subtract the tare weight from both the full kegs weight and the none-full kegs weight
liquid net weight = (full keg weigh total - keg tare weight) or (49 - 8)
wich is 41
Now for the not full weight. which is 23lbs - 8lbs(tare weight) = 15lbs
to get the % of weight left its simply (not full weight / full weight) or 15 divided by 41, which is 0.365 or roughly 37% of the liquid is left.
Now lets work in ounces. How many ounces are in my full five gallon corney keg? 128 ounces per gallon would make it (5 * 128) = 640 fl ounces.
if 100% = 640 ounces. Then 37% should be around 237 fl ounces.
237 fl ounces, each of my bottles being 12fl ounces would mean I would need around 20 bottles...
Is this correct, or does CO2 have significant weight that I should be calculating?
I don't have to be dead on, since I ussually clean more bottles and caps just incase I run into a problem, or get clumsey and drop a couple.
Also is there a simpler way to measure fluid ounces of beer on a weight scale? I noticed in this calculation I have 16.5fl ounces per pound. Or does beer variety change the actually weight per volume of beer, I could see how high alcohol beers would weigh less than low alcohol beers?
Thx