According to Bru'n Water 1 gram in 10 gallons increases my calcium to 30.3 and my bicarbonate to 96.
The molecular weight of Ca(OH2) is 74.093 grams/mol. One gram is thus 1/74.03 = 0.013508 or 13.5 mmol. Ten gallons is 37.854 L so that's 13.5/37.854 = 0.35 mmoL/L. As calcium's atomic weight is 40 mg/mmol that's 14 mg/L. With 16 mg/L calcium already in the water adding 14 gets you pretty close to 30 so check on the calcium.
OTOH your water has alkalinity of 46 which at pH 7.3 corresponds to a bicarbonate content of 53.5 mg/L. Adding 1 gram of Ca(OH)2 will raise the pH to 10.58 and in so doing convert bicarbonate to carbonate. The solution will be saturated with calcium carbonate some of which may or may not precipitate. You are effectively doing 'lime treatment' of your water. Your bicarbonate goes down but your alkalinity goes up to 80 (assuming there is no precipitation) while the bicarbonate actually goes down to about 26.
Many of the spreadsheets and calculators convert alkalinity to bicarbonate by
bicarbonate = 61*alkalinity/50.
This is OK if the pH is below 8 or so but, as in this case where the pH is higher, it's not that simple.