I came across a quote on a probrewers forum that referenced a paper AJ did. The paper wasn't available anymore (at least at that link) but the guy stated:
..."but I'd consider adding 30 mg of sodium metabisulfite or 35 mg of potassium metabisulfite per gallon of water in your situation. It would be a lot easier than crushing up a bunch of tablets. Anyway, an A.J. deLange article on chlorine/chloramine (available at
http://ajdel.wetnewf.org:81/) claims that those rates will treat the worst-case scenario of 3 mg/L chloramine. It'll also treat 6 mg/L of chlorine. If your water has 3 mg/L chloramine, the treatment will result in 3 mg/L of extra chloride ions and 8 mg/L of extra sulfate ions. If your water has 6 mg/L of chlorine, the treatment will result in 6 mg/L of extra chloride ions and 8 mg/L of extra sulfate ions. Those are pretty small changes. If your water has less chlorine or chloramine, the treatment will result in some sulfur dioxide. Some of it will be driven off in the boil, and some will react with mash compounds to form sulfate ions that will approach the 8 mg/L maximum."
In summary:
@ 30 mg SMB or 35 mg KMB per gallon:
This will treat 3 mg/L Chloramine and 6 mg/L Chlorine
@ these rates, this will produce the following
If water contains Chloramine 3 mg/L of extra chloride ions and 8 mg/L of extra sulfate
If water contains Chlorine 6 mg/L of extra chloride ions and 8 mg/L of extra sulfate
Maybe AJ can shed some light to see if he is quoted correctly.
I assume I can ratio that to see how much Chloride and Sulfate I would be adding. What about Sodium now?
Also that example is for treating chlorine/chloramine, so how would that change if you are using RO or Distilled at 100%?