Silver_Is_Money
Larry Sayre, Developer of 'Mash Made Easy'
How much alcohol does each fermentation bubble of CO2 represent? This is my initial attempt at guesstimating it:
Assumption: Airlock bubbles each contain on average 1.7 ml of CO2
Assumption: 1 mole of CO2 gas = 22.4 liters of CO2
Assumption: 1 mole of CO2 creates 1 mole of ethanol (MW = 46 grams)
Assumption: 5 gallon batch, FG = 1.010, ABW = 5%
1/22.4 = 0.044643 moles CO2 per liter of bubbles
1000/1.7 = 588.24 airlock bubbles per liter of CO2
588.24 x 22.4 = 13,177 airlock bubbles per mole of CO2, and therefore per mole of ethanol
5 gallons = 19 liters
19L x 1.010 x 1,000 = 19,190 grams (batch weight)
19,190 x 0.05 = 960 total grams of ethanol in batch for this example
960/46 = 20.87 gram/moles of ethanol for this example
20.87 x 13,177 ~= 275,000 total CO2 bubbles per batch (for 5 gal at 5% ABW)
(5% ABW)/275,000 bubbles = 0.000018182% ABW contributed by each individual CO2 bubble
0.000018182% ABW / 0.789 = 0.000023044% ABV contributed by each individual CO2 bubble
Does this seem as if I did any of it correctly? I'm aware that based upon batch temperature a certain (and fair) percentage of these 275,000 bubbles will likely remain dissolved in solution and not come out via the airlock, but if they don't come out, they are in solution, and that is telling and vital information also.
Bottom line: If you could come up with a device to count the bubbles, could you use it to determine ABV, ABW, batch completion, CO2 remaining dissolved in solution, required sugar for bottle carbonating to a given CO2 target, or any other useful measures?
Or is using bubble counting as a means of forecasting a wasted endeavor?
Assumption: Airlock bubbles each contain on average 1.7 ml of CO2
Assumption: 1 mole of CO2 gas = 22.4 liters of CO2
Assumption: 1 mole of CO2 creates 1 mole of ethanol (MW = 46 grams)
Assumption: 5 gallon batch, FG = 1.010, ABW = 5%
1/22.4 = 0.044643 moles CO2 per liter of bubbles
1000/1.7 = 588.24 airlock bubbles per liter of CO2
588.24 x 22.4 = 13,177 airlock bubbles per mole of CO2, and therefore per mole of ethanol
5 gallons = 19 liters
19L x 1.010 x 1,000 = 19,190 grams (batch weight)
19,190 x 0.05 = 960 total grams of ethanol in batch for this example
960/46 = 20.87 gram/moles of ethanol for this example
20.87 x 13,177 ~= 275,000 total CO2 bubbles per batch (for 5 gal at 5% ABW)
(5% ABW)/275,000 bubbles = 0.000018182% ABW contributed by each individual CO2 bubble
0.000018182% ABW / 0.789 = 0.000023044% ABV contributed by each individual CO2 bubble
Does this seem as if I did any of it correctly? I'm aware that based upon batch temperature a certain (and fair) percentage of these 275,000 bubbles will likely remain dissolved in solution and not come out via the airlock, but if they don't come out, they are in solution, and that is telling and vital information also.
Bottom line: If you could come up with a device to count the bubbles, could you use it to determine ABV, ABW, batch completion, CO2 remaining dissolved in solution, required sugar for bottle carbonating to a given CO2 target, or any other useful measures?
Or is using bubble counting as a means of forecasting a wasted endeavor?
Last edited: