Please educate me. Why are you calculating your current with a power factor of .8? Your element should be pretty much purely resistive, no inductance or very very little.
Here in the states it would be (8500/2)/120 = 35.5 amps. Which would require 2 X 8awg or (I think for metric) 3.5mm wire. Thats a pretty big difference between that and 3 X 14awg or 1.5mm wire if I had your electric system.
I just use .8 for safe measure as a general rule, but you're right - I could run an even bigger element on my 16 amp circuit.
The law here regarding fixed wiring: 1.5mm for 10 amp breakers, 2.5mm for 16 amp breakers, 4mm for 20 amp breakers (although I'm running 6mm to my sub panels that are connected with 20 amp breakers). So, my 3-phase socket is wired to the panel with 5x2.5mm.
For extension cords and underground cable, you can run 16 amps on 1.5mm wires but I buy 2.5mm extension cords anyway. Skinny wires start fires.