Does this look like I got the method and math right.
6kg (13lbs) of grain with PPG of 493
I get 8 Gallon at 1050
so 50*8 = 400
My mash effieciency is 400/493*100= 81%
I get 6.5 gallon in the fermenter at say 1060
So 60*6.5=390
My brewhouse efficiency is 390/493*100 = 79%
(The figures are just an example, not an actual batch)
6kg (13lbs) of grain with PPG of 493
I get 8 Gallon at 1050
so 50*8 = 400
My mash effieciency is 400/493*100= 81%
I get 6.5 gallon in the fermenter at say 1060
So 60*6.5=390
My brewhouse efficiency is 390/493*100 = 79%
(The figures are just an example, not an actual batch)