Let's look a what's going on in a mash dynamically (
https://www.homebrewtalk.com/wiki/index.php/The_Theory_of_Mashing)
- First, water has to diffuse into the grain particles in order to gelatinize and then solubilize the starches.
- Then, the soluble starch has to diffuse out of the grain into the wort
- Once the starch is in the wort, the amylase enzymes can convert it to sugars (according to what I've read, the vast majority of the enzymatic action takes place in the wort.)
So, the sugar is already in solution when it is formed. You never have solid sugar that needs to be dissolved.
Why then does your efficiency go up when you mash out? Most likely because the solubilization of the starch is not complete at the end of your mash. A test that is often suggested is to run an iodine conversion test on just the wort, and then mostly grain with a little wort. Often the wort alone tests negative (no starch), while the grain still tests positive for starch. Remember, we are dependent on diffusion for things to happen. Grain particles are very dense, so diffusion into them is very slow. Diffusion into gelatinized starch is faster, and diffusion in the wort is faster still. In practice what happens is the surface layer of a grain particle is gelatinized and solubilized before any water gets into the core of the particle. So, the surface starch is dissolved into the wort first, and then another layer, and so on, until the starch in the core is finally solubilized. Starch conversion cannot finish until the core has been solubilized.
With a normal grain crush, a 60 minute mash may not be long enough to complete conversion of the cores of the particles. When you mash out, diffusion speeds up, as does the reaction rate of the amylase enzyme, and also the denaturing rate of the enzyme. So, you are getting a little more starch conversion during the mash out, at least until the amylase is completely denatured. With a longer mash, or finer crush, the efficiency gain from a mash out will decrease or even disappear.
Brew on