I am considering doing a Oatmeal stout PM and still researching the brewing process. I have one extract brew under my belt and numerous batches of wine/mead. I am taking a look at the PM approach and trying to figure out more on the mash process when using flaked oatmeal in mash. I have noticed pm kits with oatmeal usually have around half the oatmeal that all grain recipes use and have assumed its due to the need to have a certain amount of base grain to help the conversion process. I found this one BYO article getting close to my answer:
http://***********/component/resource/article/511-countertop-partial-mashing
Under the "Four pounds of grain" the author states that you can do 13oz of adjunct grain using 2 row and up to 19oz if using 6 row but does not state how those numbers are calculated. Is there a formula or general guideline of how much base grain is needed for a certain amount of adjunct? I would like to convert a AG Oatmeal stout recipe which uses around 1-1.5lbs of oatmeal.
http://***********/component/resource/article/511-countertop-partial-mashing
Under the "Four pounds of grain" the author states that you can do 13oz of adjunct grain using 2 row and up to 19oz if using 6 row but does not state how those numbers are calculated. Is there a formula or general guideline of how much base grain is needed for a certain amount of adjunct? I would like to convert a AG Oatmeal stout recipe which uses around 1-1.5lbs of oatmeal.