snailsongs
Well-Known Member
In Jamil Z. and John P.'s recipe book, there are instructions for performing a partial boil (for those of us still stuck with 5 gallon brew pots), but there is one part of the instructions that are unclear to me. They say that the wort that is boiled needs to be the same gravity as the target OG, and that the steeping grains need to be factored into the boil gravity too (so that the pre-boil extract is less than an even 50% of the total bill). The calculations for figuring this are, for the recipe I am working out, as follows:
2.65 lbs (steeping grain) x 24ppg/3gal = ? (gravity points at 70% yield)
then you are supposed to take those points and subtract them from the target gravity, and then use that gravity number to determine the amount of extract you need, with another equation I don't understand.....The math kills me. Is all this really necessary? How much of a difference will it make if my boil gravity is little different from the final gravity? thanks in advance for your help.
2.65 lbs (steeping grain) x 24ppg/3gal = ? (gravity points at 70% yield)
then you are supposed to take those points and subtract them from the target gravity, and then use that gravity number to determine the amount of extract you need, with another equation I don't understand.....The math kills me. Is all this really necessary? How much of a difference will it make if my boil gravity is little different from the final gravity? thanks in advance for your help.