Hey all,
I am just wondering how you all calculate efficiency... I went to a site that basically says every grain has a maximum theoretical yield, and you take your lbs of whatever grain(s) it is, and multiply by the maximum theoretical yield
(listed as "points" from 29 to 37 depending on grain) giving you a magic number that you would reach if you had 100% efficiency (the site has a chart of common grains along with their theoretical). so lets say you had four different grains: ( 4 x 37 ) + ( 2.5 x 33 ) + ( 0.86 x 34 ) + ( 0.13 x 34 ) = 264 points.. Then you divide this # by the gallons of wort in your recipe, giving you a percentage. lets say 264 divided by 3.5 gallons of wort would be .75... This then equates to an OG 1.075... So if you had perfect efficiency, you would expect an OG of 1.075.. If your measured OG turned out to be 1.058, then we have 58 divided by 75, which gives an extraction efficiency of .77 or 77%. Is this the method most of you use? Or is there another methoid I should know about.. Maybe soemthing a little more liberal, since using this method, I have only achieved an efficiency of 61% my last couple brews... heheh
thanks
PS- This information came from http://www.hbd.org/uchima/tech/efficiency.html
I am just wondering how you all calculate efficiency... I went to a site that basically says every grain has a maximum theoretical yield, and you take your lbs of whatever grain(s) it is, and multiply by the maximum theoretical yield
(listed as "points" from 29 to 37 depending on grain) giving you a magic number that you would reach if you had 100% efficiency (the site has a chart of common grains along with their theoretical). so lets say you had four different grains: ( 4 x 37 ) + ( 2.5 x 33 ) + ( 0.86 x 34 ) + ( 0.13 x 34 ) = 264 points.. Then you divide this # by the gallons of wort in your recipe, giving you a percentage. lets say 264 divided by 3.5 gallons of wort would be .75... This then equates to an OG 1.075... So if you had perfect efficiency, you would expect an OG of 1.075.. If your measured OG turned out to be 1.058, then we have 58 divided by 75, which gives an extraction efficiency of .77 or 77%. Is this the method most of you use? Or is there another methoid I should know about.. Maybe soemthing a little more liberal, since using this method, I have only achieved an efficiency of 61% my last couple brews... heheh
thanks
PS- This information came from http://www.hbd.org/uchima/tech/efficiency.html