McKnuckle
Well-Known Member
Consider if you will, a kettle full of cooled wort. There are no hops in it, only liquid, sugars, and break material.
The apparent volume of the wort, measured with a ruler in the kettle to the nearest 1/16" and visually confirmed in the fermenter, is 2.080 gallons.
The wort weighs 8.049 Kg. Specific gravity measured with a hydrometer is 1.056.
8.049 Kg of pure water would be 8.049 Liters. I’ve been accounting for sugar by dividing this by OG, or 8.049 / 1.056 = 7.622 L of water in the solution. This converts to 2.014 gallons. If I consider my measured volume (2.080 gal), that leaves me with 0.066 gal to account for, a little over one cup. I’m guessing this is the break material.
Does this analysis of the wort components sound correct?
The apparent volume of the wort, measured with a ruler in the kettle to the nearest 1/16" and visually confirmed in the fermenter, is 2.080 gallons.
The wort weighs 8.049 Kg. Specific gravity measured with a hydrometer is 1.056.
8.049 Kg of pure water would be 8.049 Liters. I’ve been accounting for sugar by dividing this by OG, or 8.049 / 1.056 = 7.622 L of water in the solution. This converts to 2.014 gallons. If I consider my measured volume (2.080 gal), that leaves me with 0.066 gal to account for, a little over one cup. I’m guessing this is the break material.
Does this analysis of the wort components sound correct?