jack13
Well-Known Member
The OG was 1.066 on a coffee stout. I let it fully ferment, then racked it (4.75 gallons) onto 1 gallon of coffee in a secondary.
I realize now I should have taken a gravity reading before I transfered, but I did not. Anyway, it's now 83% beer of an unknown SG and 17% coffee.
The FG (with the coffee in there) is 1.014. Now I'm not sure how to figure out my ABV. So...
Question #1. Can I assume regular old dilution rules apply, and the SG before I added the coffee was 1.017?
I came up with 1.017 according the following logic...or "logic". Since I have an 83% beer / 17% coffee solution, with a known weighted average of 1.014, I took a weighted average formula and algebra-ed it to give me the unknown reading of the "original" beer.
1.014 (the known weighted average) = (0.83)X + (0.17)1.000
And so (1.014 - 0.17) / 0.83 = 1.017
Question #2. IF that's correct, it would mean I had 1.066 wort that was fermented down to 1.017 (6.43% ABV). I then diluted that with 0.00 ABV coffee, so then I'd just do 6.43 x 0.83= 5.34% ABV?
I realize now I should have taken a gravity reading before I transfered, but I did not. Anyway, it's now 83% beer of an unknown SG and 17% coffee.
The FG (with the coffee in there) is 1.014. Now I'm not sure how to figure out my ABV. So...
Question #1. Can I assume regular old dilution rules apply, and the SG before I added the coffee was 1.017?
I came up with 1.017 according the following logic...or "logic". Since I have an 83% beer / 17% coffee solution, with a known weighted average of 1.014, I took a weighted average formula and algebra-ed it to give me the unknown reading of the "original" beer.
1.014 (the known weighted average) = (0.83)X + (0.17)1.000
And so (1.014 - 0.17) / 0.83 = 1.017
Question #2. IF that's correct, it would mean I had 1.066 wort that was fermented down to 1.017 (6.43% ABV). I then diluted that with 0.00 ABV coffee, so then I'd just do 6.43 x 0.83= 5.34% ABV?