Exactly. Im assuming this is for a rims configuration? Thats the only scenerio where I could see this making any sense at all.I like this way better...
I like this way better...
All else equal, your power will be the same regardless of the voltage. Power is voltage times amps and your element is going to pull the same power regardless of the voltage. It will however, draw fewer amps at 220V.
Also, all else isn't equal in this case. Heating elements are rated for either 220v or 110V not both. You can run a 220V element on 110V but there's no reason to. Your PID is going to control your duty cycle and thus regulate your power during the mash so there's no reason to reduce voltage. I'd just go with a straight 220V system and keep things simple.
I'm using this in a single pot to mash and boil. I thought it would be good to back power down on mash.
I'm just going to get rid of 1 ssr and use a spdt mechanical relay to do switch. Thanks for all the comments.
I'm just going to get rid of 1 ssr and use a spdt mechanical relay to do switch. Thanks for all the comments.
I have 3 wire 220v, 110v, 110v and ground. So I have to use ground for neutral is that a problem?
I my fuse box the bare wire going to my range rect goes to ground.
I accidently liked this ... as already stated running a 240v element on 120v will quarter the power output... I agree with the point of the second comment though. Using a quality pwm controller like a pid with manual mode with a short cycle time will do the same thing in practical terms...All else equal, your power will be the same regardless of the voltage. Power is voltage times amps and your element is going to pull the same power regardless of the voltage. It will however, draw fewer amps at 220V.
Also, all else isn't equal in this case. Heating elements are rated for either 220v or 110V not both. You can run a 220V element on 110V but there's no reason to. Your PID is going to control your duty cycle and thus regulate your power during the mash so there's no reason to reduce voltage. I'd just go with a straight 220V system and keep things simple.
No, this is completely wrong.
The element has a fixed resistance. The current will be determined by the voltage: I = V/R
The element will draw twice the current at 230V as it will at 115V.
Since we have a current source (the supply voltage will stay at 115 or 230V, regardless of current supplied),the power will be determined by the voltage and the resistance of the element: P = VI = V*V/R = V²/R
The power will drop to one quarter when dropping the voltage from 230V to 115V.
This is also somewhat wrong. The PID cycles on and off on a varying pulse width (PWM) to reduce the average power. During the "on" part of the cycle, the element will be running at the full power allowed by the supply voltage. If the PID PWM cycle is long (few seconds), there may be enough energy supplied to cause scorching, even if the average power is low.
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