Utilization Equation question

richwyso said:

I have been reading this book from how to brew from john palmer and i wonder if anyone out there is familiar with the equation below. More specifically, its been driving me crazy all morning trying to figure out where the 7/10 came from. Does anyone know? I have posted below the quote from the book:

For example, to calculate the utilization for a boil gravity of 1.057 at 30 minutes, look at the utilization values for 1.050 and 1.060. These are .177 and .162, respectively. There is a difference of 15 between the two, and 7/10ths of the difference is about 11, so the adjusted utilization for 1.057 would be .177 - .011 = 0.166.

dont know where the 7/10 came from. thanks

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Kingbogart said:

There are 10 points between 1.050 and 1.060. You are at 1.057, which is 7/10 of those points. The difference between 1.050 and 1.060 is 15, 7/10*15 = 11.

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Kingbogart said:

There are 10 points between 1.050 and 1.060. You are at 1.057, which is 7/10 of those points. The difference between 1.050 and 1.060 is 15, 7/10*15 = 11.

Click to expand...