DakotaPrerunner
Well-Known Member
Where O is your desired oxygen in mg/l(ppm), and B is you batch size in liters. this formula assumes 32g of oxygen per mole, that you get 100% transfer and the ideal gas law that 22.4l per mole at one atmosphere is close enough for brewing.
(((OxB)/1000)/32)22.4=liters of oxygen.
example lets say you want 12ppm for 5 gallons (20L) of wort
(((12x20)/1000)/32)22.4=
((240/1000)/32)22.4=
(.24/32)22.4=
(0.0075)22.4=0.168 liters of oxygen
using, o2 needed/flow lpm = time, set your flow meter for 0.2lpm and run your O2 for 50.4 seconds.
0.168/0.2 = .84 minutes = 50.4 seconds.
Does this help or am I way off my rocker trying to use math to brew beer.:cross:
(((OxB)/1000)/32)22.4=liters of oxygen.
example lets say you want 12ppm for 5 gallons (20L) of wort
(((12x20)/1000)/32)22.4=
((240/1000)/32)22.4=
(.24/32)22.4=
(0.0075)22.4=0.168 liters of oxygen
using, o2 needed/flow lpm = time, set your flow meter for 0.2lpm and run your O2 for 50.4 seconds.
0.168/0.2 = .84 minutes = 50.4 seconds.
Does this help or am I way off my rocker trying to use math to brew beer.:cross: