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Old 02-28-2009, 05:13 AM   #1
Gristulin
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Default any way?

i have read a recipe that is an extract, but i want to brew it all grain. is there an easy way to figure out how much grain to use when compared to extracts? i want to use the Belgian Pale Ale, "coopers" recipe that is in the jan/feb issue of Zymurgy. im learnin, but slow. thanx for everything so far!!!!!!!!!!
Zac

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Old 02-28-2009, 05:44 AM   #2
eriktlupus
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using the formula in my sig but replce 36 with 44 for dme or keep it 36 for lme, don't allow for brewhouse efficiency in either case

example:some ipa (5g)
6#dme
3.3# lme
.5# carapils

add the values from the dme and lme
(6# x 44)+(3.3 x 36)/5g=76.56

76.56 / brewhouse eff(.80 for me)=95.7
95.7 x 5g / 36ppp=13.3# of grain for replacement of all extracts use 2row in this case

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extraction calculator
grains in pounds(G) X 36(average points per gallon of grains) / batch size in gallons(g) = maximum efficiency(ME)
OG / ME = brewhouse efficiency


Last edited by eriktlupus; 02-28-2009 at 05:58 AM.
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Old 02-28-2009, 05:56 AM   #3
Gristulin
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im sorry, i dont understand? is there a link or somethin that may help a noob?
Zac

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Old 02-28-2009, 06:05 AM   #4
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check above^^^^

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primary1 :UTOPIA BABY(still searching for it)
secondary:middling bastard ipa
kegged:simcoe blonde, crystal pale ale, yellow jacket golden ale, lemon shandy blonde
DRINKIN DAWG BREWERY
LET'S GO RED WINGS


join michigan mashers here

extraction calculator
grains in pounds(G) X 36(average points per gallon of grains) / batch size in gallons(g) = maximum efficiency(ME)
OG / ME = brewhouse efficiency

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Old 02-28-2009, 06:17 AM   #5
Gristulin
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i stunderand. thanx.
zac

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