I have done a couple extra brew batches with my friends but we woud like to move to all-grain brewing. For this first batch we are going to do everything by hand with extract brew equipment. With regard to answering the question, just assume I have one pot/fermenter/piece-of-equipment that is large enough to handle the volume required.
I am looking to order an all-grain recipe kit (Hop Head Double IPA) from Midwestsupplies.com. I am trying to figure out how much wort volume I should expect. The ingredients are as follows:
14 lbs. Domestic 2-Row barley malt
4 oz. Aromatic
12 oz. Caramel 60L
8 oz. Victory
1 oz. Chinook
1 oz. Cascade
1 oz. Centennial
1 oz. Crystal
2 oz. whole hops (dry hop)
priming sugar
yeast
If I use 1.5 quarts/lb for the mash [1.5 qt. x (1/4 + 3/4 + 1/2 + 14) = 23.25 qt. or 5.81 gallons] and 0.5 gallons/lb for the sparge [0.5 gal. x (1/4 + 3/4 + 1/2 + 14) = 7.75 gallons] then would I end up with 13.56 gallons [5.81 + 7.75 = 13.56] for total volume, not counting any evaporation? My initial thought is that I could end up with 10 gallons of wort after the boil. Is that reasonable or just a bad rookie estimate?
Sorry for the sloppy math equations.
I am looking to order an all-grain recipe kit (Hop Head Double IPA) from Midwestsupplies.com. I am trying to figure out how much wort volume I should expect. The ingredients are as follows:
14 lbs. Domestic 2-Row barley malt
4 oz. Aromatic
12 oz. Caramel 60L
8 oz. Victory
1 oz. Chinook
1 oz. Cascade
1 oz. Centennial
1 oz. Crystal
2 oz. whole hops (dry hop)
priming sugar
yeast
If I use 1.5 quarts/lb for the mash [1.5 qt. x (1/4 + 3/4 + 1/2 + 14) = 23.25 qt. or 5.81 gallons] and 0.5 gallons/lb for the sparge [0.5 gal. x (1/4 + 3/4 + 1/2 + 14) = 7.75 gallons] then would I end up with 13.56 gallons [5.81 + 7.75 = 13.56] for total volume, not counting any evaporation? My initial thought is that I could end up with 10 gallons of wort after the boil. Is that reasonable or just a bad rookie estimate?
Sorry for the sloppy math equations.