TexasLonghorn
Member
Hi all,
I was doing some reading on bottling and priming sugar equations as I am trying to be a little more exacting on my volumes of CO2 than I have in the past. For this batch, I'm going for about 2.5 volumes of CO2. I've found several calculators, and they all give the same answer as to how much sugar to use. I've also found equations which yield the same answer (about 4.24 oz of corn sugar for 4.75 gallons of 70 degree F beer). I'm using this equation from Zymurgy: PS (grams) = 15.195 Vb ( CD - 3.0378 + .050062 * T - .00026555 * T * T ). Vb is beer volume and CD is desired volumes of CO2. I don't know how this equation was derived (if someone knows, that would be great to see).
However, I came across this article: Link which talks about accounting for the volumes of CO2 already in the beer from fermentation. My question is: does the above equation already account for the CO2 in the beer prior to priming, or should my CD in the above equation be (2.5 - pre-existing CO2) instead of just 2.5?
Thanks for any help.
I was doing some reading on bottling and priming sugar equations as I am trying to be a little more exacting on my volumes of CO2 than I have in the past. For this batch, I'm going for about 2.5 volumes of CO2. I've found several calculators, and they all give the same answer as to how much sugar to use. I've also found equations which yield the same answer (about 4.24 oz of corn sugar for 4.75 gallons of 70 degree F beer). I'm using this equation from Zymurgy: PS (grams) = 15.195 Vb ( CD - 3.0378 + .050062 * T - .00026555 * T * T ). Vb is beer volume and CD is desired volumes of CO2. I don't know how this equation was derived (if someone knows, that would be great to see).
However, I came across this article: Link which talks about accounting for the volumes of CO2 already in the beer from fermentation. My question is: does the above equation already account for the CO2 in the beer prior to priming, or should my CD in the above equation be (2.5 - pre-existing CO2) instead of just 2.5?
Thanks for any help.