Is there a formula to convert recipes from partial mash to AG?

[Conodor]

https://www.homebrewtalk.com/f78/vanilla-bourbon-winter-ale-35863/


i want to make a vanilla bourbon ale, i find this recipe but it's a partial mash. is there a way to look at the LME and replace it with some grain to do an all grain?


5.00 lbs. Generic LME - Weizen Generic 1.035
3.00 lbs. Generic LME - Extra Light Generic 1.035

this is what is given in the recipe.


thanks

 

[MachineShopBrewing]

I think it is something like .6 lbs of LME to 1 lb of base malt. Depending on your efficiency of course

 

[Grizzlybrew]

Well, you should be able to look at the percentages of each extract and go from there. Ray Daniels (in his book, Designing Great Beers) describes pretty well how to convert recipes, not only the quantities of ingredients, but how different grains must be used by the extract brewer trying to replicate AG brews. I definitely recommend the read.

 

[Conodor]

Thanks for the tips, i will check into that book.

 

[homebrewer_99]

I think it is something like .6 lbs of LME to 1 lb of base malt. Depending on your efficiency of course

That's close, but not right.

1 lb grain = .75 lb LME = .6 lb DME

Be forewarned though, a lot of people don't measure out their LME/DME properly...0.75 lb LME is actually 12 oz and 0.6 lb DME is 9.6 oz.

For future measurements sake, 0.1 (decimal) is 1.6 oz.