why do you add the five for the pils but not the amber?
? he's not adding 5 onto anything.
The formula is to multiple the weight of each grain by the pppg for each grain. Add those numbers all up. Then divide by the volume of wort you have.
But note... this is only one type of efficiency. This one is "brewhouse efficiency" and is based on volume and gravity you have at the very end of the session, in your fermenter.
You can measure efficiency in other ways. Like... measuring the gravity and volume in your kettle, before you go to the fermenter. This number is higher than the brewhouse efficiency because you probably have a volume loss b/c of deadspace in the kettle.
Example: 10# of 2-row. pppg of 36. At the end of the boil, let's say you have 5.5 gallons of 1.053 wort in your kettle.
max theoretical gravity of 5.5 gallons: (10*36)/5.5 = 65
so 100% efficiency would give you 1.065 OG in 5.5 gallons.
You got 1.053 OG, so (53/65) = 81.5% efficiency.
But, then you run it into your fermenter and end up with only 5 of that 5.5 gallons. The other 0.5 gallons is dead space or crud in the fermenter. Gravity is still 1.053.
max theoretical gravity of 5 gallons: (10*36)/5 = 72
so 100% efficiency would give you 1.072 OG in 5 gallons.
You got 1.053 OG, so (53/72) = 73.6% efficiency.