Microphobik
Well-Known Member
- Joined
- Apr 15, 2013
- Messages
- 320
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Sorry guys/gals, I know this has been asked a lot, but after an hour or two of searching I'm just not coming upon the info I'm looking for.
I'd like to start brewing with the no sparge method to simplify my brew day a bit, and also start playing with Partigyles fairly regularly.
I'm looking for a simple way to calculate how big of a mash tun I would need.
So lets say, for example, I want to be able to brew a barleywine with 23lbs of grain to collect 7.5 gallons of pre-boil wort (to be boiled down to 6 or less)...
How big does my mash tun need to be if I want to use the no sparge method?
And how much water do I need to add to that 23lbs of grain?
I'm super confused by this for some reason and my calculations don't seem to be right whenever I pull out the calculator or start tinkering with the mash calculators I've been able to find.
Thanks in advance.
I'd like to start brewing with the no sparge method to simplify my brew day a bit, and also start playing with Partigyles fairly regularly.
I'm looking for a simple way to calculate how big of a mash tun I would need.
So lets say, for example, I want to be able to brew a barleywine with 23lbs of grain to collect 7.5 gallons of pre-boil wort (to be boiled down to 6 or less)...
How big does my mash tun need to be if I want to use the no sparge method?
And how much water do I need to add to that 23lbs of grain?
I'm super confused by this for some reason and my calculations don't seem to be right whenever I pull out the calculator or start tinkering with the mash calculators I've been able to find.
Thanks in advance.