ultravista
Well-Known Member
I have a few questions about how Beersmith calculates mash water and sparge water to result in the end result batch size.
For example. When looking at Yoopers Dead Guy Ale clone, the total step-mash volume is 6.25 gallons (12.5 # grain) and the sparge water is 2.21 gallons.
If figuring .12 gallons absorbtion per pound of grain, the post-mash volume (-1.5 gallon) would be 4.75 gallons.
4.75 mashed gallons + 2.21 sparged runnings = 6.96 pre-boil gallons.
If figuring .11 gallon loss per hour, the post-boil volume for one hour is 6.96*.11 or .77 gallons (3/4 gal) lost to evaporation resulting in 6.19 gallons post-boil.
Considering the target volume is 5.25 gallons, where did the other 0.94 (let's call it 1 gallon) of water go?
For example. When looking at Yoopers Dead Guy Ale clone, the total step-mash volume is 6.25 gallons (12.5 # grain) and the sparge water is 2.21 gallons.
If figuring .12 gallons absorbtion per pound of grain, the post-mash volume (-1.5 gallon) would be 4.75 gallons.
4.75 mashed gallons + 2.21 sparged runnings = 6.96 pre-boil gallons.
If figuring .11 gallon loss per hour, the post-boil volume for one hour is 6.96*.11 or .77 gallons (3/4 gal) lost to evaporation resulting in 6.19 gallons post-boil.
Considering the target volume is 5.25 gallons, where did the other 0.94 (let's call it 1 gallon) of water go?