Hi All:
First post to a great forum! I've been lurking for a month now.
I have a question about the "yeast efficiency" concept.
I have only brewed two batches so far (BTW, this is very fun) and here are my numbers:
1st Beer (all extract) - 1.052 OG @70F, 2nd reading of 1.020@70F. Calculation is as follows:
(1.052 - 1.020) x 105 = .032 x 105 = alcohol by weight (3.36%). To convert to volume multiply the result (.032) by 1.25 = 4.2% by volume.
Is this first beer's efficiency?: (1.020 / 1.052) * 100 = 96.95%
AND
2nd Beer (partial mash) - 1.053 OG @130F. Add .013 for temp adjustment = 1.066 OG . 2nd reading of 1.020 @70F.
(1.066 - 1.020) x 105 = 4.83% by weight
4.83 x 1.25 = 6.038 by volume
Is this second beer's efficiency?: (1.020 / 1.066) * 100 = 95.68%
Are my numbers on target here?
If I'm calculating yeast efficiency correctly, are these numbers good?
Thanks,
Spindrift
Edited for a typo.
First post to a great forum! I've been lurking for a month now.
I have a question about the "yeast efficiency" concept.
I have only brewed two batches so far (BTW, this is very fun) and here are my numbers:
1st Beer (all extract) - 1.052 OG @70F, 2nd reading of 1.020@70F. Calculation is as follows:
(1.052 - 1.020) x 105 = .032 x 105 = alcohol by weight (3.36%). To convert to volume multiply the result (.032) by 1.25 = 4.2% by volume.
Is this first beer's efficiency?: (1.020 / 1.052) * 100 = 96.95%
AND
2nd Beer (partial mash) - 1.053 OG @130F. Add .013 for temp adjustment = 1.066 OG . 2nd reading of 1.020 @70F.
(1.066 - 1.020) x 105 = 4.83% by weight
4.83 x 1.25 = 6.038 by volume
Is this second beer's efficiency?: (1.020 / 1.066) * 100 = 95.68%
Are my numbers on target here?
If I'm calculating yeast efficiency correctly, are these numbers good?
Thanks,
Spindrift
Edited for a typo.