Calculating strike water temp - HELP

I saw other threads but I am having a tough time figuring this out.

Initial Infusion Equation:
Strike Water Temperature Tw = (.2/r)(T2 - T1) + T2

where:
r = The ratio of water to grain in quarts per pound.
11.875 lbs of grain (divided by) 3.7 gal (1.25 gt per lb) = .31


T1 = The initial temperature (¡F) of the mash.
60'

T2 = The target temperature (¡F) of the mash.
165'

Tw = The actual temperature (¡F) of the infusion water.


So: (.2 / .31 = .64)(165 -60 = 105) + 165
So: .64 x 105 +165
So: 67.5 +165 = 200+... That can't be right... What am I doing wrong???

in your equation r should be 1.25 not .31

Thanks for the note on that one. That still leaves my strike water temp at 182'. Isn't that a little high? or is that accounting for heat loss due to the added grain?

I agree that r should be between 1 and 2, and 1.25 is a good starting point
But surely you're not going to mash at 165. 154 seems to be a reasonable value
So: (.2 / 1.25 = .16)(154 - 60 = 94) + 154
So:.16 * 94 + 154 = 169

That looks pretty reasonable to me.
-a.

http://www.garagebrewers.com/forum/topic?f=14&t=1072 is the recipe I have planned to follow... Guy says its legit. I know not to believe everything I read... but

thanks for the notes.

I see a mash temp of 156 vs 165. Which is a perfectly reasonable temp for a full bodied beer.

hi dyslexia how are you! sorry everyone, AJF as exactly right...