Hi all!
I have an all grain recipe which I want to try for my "first" go (I say "first" as my actual first was awful, so I'm not counting that...). I understand and am happy with most of it, but one part says "total liquor = 28.1L, Mash liquor = 11.8L".
Am I right in thinking that I use 11.8L to mash, the same again to sparge and then top the fermenting barrel up to 28.1L with cold water once it's at that point? Or would I be boiling with 28.1L?
28.1L seems little excessive as this is a recipe for 19 litres of beer, so am I expected to lose 9.1L during the boil? it would seem a lot!
I have an all grain recipe which I want to try for my "first" go (I say "first" as my actual first was awful, so I'm not counting that...). I understand and am happy with most of it, but one part says "total liquor = 28.1L, Mash liquor = 11.8L".
Am I right in thinking that I use 11.8L to mash, the same again to sparge and then top the fermenting barrel up to 28.1L with cold water once it's at that point? Or would I be boiling with 28.1L?
28.1L seems little excessive as this is a recipe for 19 litres of beer, so am I expected to lose 9.1L during the boil? it would seem a lot!