WVBeerBaron
Well-Known Member
I have a noob question regarding the volume of water collected after the mash and sparge.
Lets talk about a big high gravity beer. Say for example I have 15lbs of grain to mash. I would use about 4.5 gallons of mash water because of the ratio of 1lb of grain to 1.25q water. ok, then 1/2 gallon sparge water for every pound of grain comes to 7.5 gallon sparge water. I understand there is some grain absorption and evaporation in the boil but this seems like I will collect 12 gallon of wort (4.5 gallon mash + 7.5 gallon sparge = 12 gallons). how does this make a 5 gallon batch of beer????? Boil for 3 days strait?? Thanks for any help.
Lets talk about a big high gravity beer. Say for example I have 15lbs of grain to mash. I would use about 4.5 gallons of mash water because of the ratio of 1lb of grain to 1.25q water. ok, then 1/2 gallon sparge water for every pound of grain comes to 7.5 gallon sparge water. I understand there is some grain absorption and evaporation in the boil but this seems like I will collect 12 gallon of wort (4.5 gallon mash + 7.5 gallon sparge = 12 gallons). how does this make a 5 gallon batch of beer????? Boil for 3 days strait?? Thanks for any help.