Here is the scenario:
1) inoculate 10 mL of 1.040 wort with loopful of yeast from an agar plate; 24 hours with aeration.
2) step up to 100 mL of 1.040 wort; 24 hours on stir plate.
3) step up to 1 L of 1.040 wort; 24 hours on stir plate.
What is the theoretical cell count? The online calculators don't seem to account for this scenario. Perhaps realistically, most of them start with packets of yeast and account for viability of the packet. I'm thinking maybe the braukaiser calculator comes the closest to reality? If I put in 1 billion cells as the starting cell count, the calculator gives 161 billion cells for a 1 L 1.040 gravity starter on a stir plate. Using the same inputs, the C. White stir plate calculator gives 7 billion cells (both calculations performed here: http://www.brewersfriend.com/yeast-pitch-rate-and-starter-calculator/). One of these has to be wrong because the difference is ridiculously big.
Any thoughts?
1) inoculate 10 mL of 1.040 wort with loopful of yeast from an agar plate; 24 hours with aeration.
2) step up to 100 mL of 1.040 wort; 24 hours on stir plate.
3) step up to 1 L of 1.040 wort; 24 hours on stir plate.
What is the theoretical cell count? The online calculators don't seem to account for this scenario. Perhaps realistically, most of them start with packets of yeast and account for viability of the packet. I'm thinking maybe the braukaiser calculator comes the closest to reality? If I put in 1 billion cells as the starting cell count, the calculator gives 161 billion cells for a 1 L 1.040 gravity starter on a stir plate. Using the same inputs, the C. White stir plate calculator gives 7 billion cells (both calculations performed here: http://www.brewersfriend.com/yeast-pitch-rate-and-starter-calculator/). One of these has to be wrong because the difference is ridiculously big.
Any thoughts?