Silver_Is_Money
Larry Sayre, Developer of 'Mash Made Easy'
If all you know with regard to your water is its total hardness, you can make an educated guess at determining its approximate ppm Ca++ and Mg++ ion concentrations as follows:
First, convert whatever units your total hardness is reported in into units of ppm (mg/L) of total hardness "as CaCO3".
Next, it appears as if an aggregate average of all of the worlds fresh water indicates that "on average" roughly 70% of fresh waters "total hardness" is derived from Calcium, with roughly 30% from Magnesium.
MW of CaCO3 = 100.0869
MW of Ca++ = 40.078
MW of Mg++ = 24.305
100.0869/40.078 = 2.4973
100.0869/24.305 = 4.118
Therefore:
Total Hardness (as CaCO3) = 2.4973(Ca++) + 4.118(Mg++)
Therefore, on average:
Ca++ ~= (0.70*TH)/2.4973
Mg++ ~= (0.30*TH)/4.118
First, convert whatever units your total hardness is reported in into units of ppm (mg/L) of total hardness "as CaCO3".
Next, it appears as if an aggregate average of all of the worlds fresh water indicates that "on average" roughly 70% of fresh waters "total hardness" is derived from Calcium, with roughly 30% from Magnesium.
MW of CaCO3 = 100.0869
MW of Ca++ = 40.078
MW of Mg++ = 24.305
100.0869/40.078 = 2.4973
100.0869/24.305 = 4.118
Therefore:
Total Hardness (as CaCO3) = 2.4973(Ca++) + 4.118(Mg++)
Therefore, on average:
Ca++ ~= (0.70*TH)/2.4973
Mg++ ~= (0.30*TH)/4.118
