Hi,
I had problem with my first two beer and ended up evaporating way too much water. In the recipe I did there is an OG you have to achieve, but you have to measure it to know if you reached it. I measured it a few time in the boil to figure out at which time I would achieve the desired gravity (linearly). The problem is I think evaporation speed isn't constant in time so I end up coming back after the calculated time and there is too much boiled off volume. Evaporation in my setup is fast and it seems like it speed up during the boil. I look at it, not much water has evaporated for the given time, I go away for a short while and come back to see that it evaporated too much.
I am trying to mark my kettle inside so I know what volume there is inside just by looking. If I achieve the volume I want I will be able to achieve an ok OG and final volume. It is quicker and safer just to take a look inside. I will know right away if I am close to my OG and if I have to stay around.
I think there is a problem with your equation because the mass on the left isn't equal to the mass to the right. A gravity is the density of something divided by the density of water. If you mutplity a gravity by the density of water, you will get a density. A density is a mass divided by a volume. If you multiply the density by the volume, you will get a mass.
The total mass at the beggining of the boil is equal to the mass at the end of the boil and the mass of the evaporated water. Your equation states that the mass at the beggining of the boil (divided by a constant which is the density of water) is equal to the mass at the end of the boil (divided by the some constant which is the density of water). This gives OG*volume=OG2*volume2 (density*volume *cte= density 2* volume 2 *cte). This is not true because water was evaporated, so the mass in your kettle at the end is less than at the beggining.
The interface of brewing software is kind of an hassle to deal with and not that useful. I would only like to know if the approach in my original post is valid. The problem would be that evaporated water don't have a density of 1 water (not pure water). It would fluctuate with the composition of the wort and that would be plausible. But is it a good approximation? Does anyone do the same approach?