thehopbandit
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In regards to mash/lauter tun deadspace in BeerSmith, I have a couple questions.
Assume a recipe with 12 lbs of malt, batch sparging. I have been messing around with the tun deadspace box to see how it affects the calculations. I am very confused, however, because BS doesn't seem to be calculating anything different other than water volume used.
Assuming constant other variables between these two situations, look at the following:
Deadspace setting at 0 gallons:
Mash water: 4.5 gallons
Sparge water: 4.42 gallons
Pre-boil: 7.48 gallons (8.92 gallons total water - 1.44 gallons grain absorption - 0 gallons of deadspace)
OG: 1.060
Deadspace setting at 1 gallon:
Mash water: 4.5 gallons
Sparge water: 5.42 gallons
Pre-boil: 7.48 gallons (9.92 gallons total water - 1.44 gallons grain absorption - 1 gallon of deadspace)
OG: 1.060
I'm confused here. Wouldn't accounting for the deadspace (i.e. adding an additional gallon of water to the mash/sparge that gets left behind) further "dilute" the dissolved sugars, making the OG less overall? According to BeerSmith, the only change that happens when accounting for the deadspace is that you just add an additional gallon of sparge water to make up for the one gallon that gets left behinds.
In the first example, the only water lost is water absorbed by the grains. In the second example, you have water absorbed by the grain but also 1 gallon of water (that has mixed sugars in) that is going to stay behind. In essence, both examples have the same, constant amount of sugar available. You are producing 8.5 gallons of pre-boil wort (1g is left behind as deadspace) in the second example and 7.5 gallons in the first. Surely the OG's would be different?
With a constant amount of sugar that presumably dissolves evenly, it doesn't seem possible that the OG's would be the same. If it were, then it would mean you could (theoretically) have a tun with 10 gallons of deadspace and the OG wouldn't change?
To illustrate another way. With the deadspace at 0 gallons, we are dissolving the sugars from 12 lbs of malt into ~8.92 gallons of water. With the deadspace at 1 gallon, we are dissolving the sugars from 12 lbs of malt into ~9.92 gallons of water. Why would BeerSmith calculate the OG as the same in both situations?
Assume a recipe with 12 lbs of malt, batch sparging. I have been messing around with the tun deadspace box to see how it affects the calculations. I am very confused, however, because BS doesn't seem to be calculating anything different other than water volume used.
Assuming constant other variables between these two situations, look at the following:
Deadspace setting at 0 gallons:
Mash water: 4.5 gallons
Sparge water: 4.42 gallons
Pre-boil: 7.48 gallons (8.92 gallons total water - 1.44 gallons grain absorption - 0 gallons of deadspace)
OG: 1.060
Deadspace setting at 1 gallon:
Mash water: 4.5 gallons
Sparge water: 5.42 gallons
Pre-boil: 7.48 gallons (9.92 gallons total water - 1.44 gallons grain absorption - 1 gallon of deadspace)
OG: 1.060
I'm confused here. Wouldn't accounting for the deadspace (i.e. adding an additional gallon of water to the mash/sparge that gets left behind) further "dilute" the dissolved sugars, making the OG less overall? According to BeerSmith, the only change that happens when accounting for the deadspace is that you just add an additional gallon of sparge water to make up for the one gallon that gets left behinds.
In the first example, the only water lost is water absorbed by the grains. In the second example, you have water absorbed by the grain but also 1 gallon of water (that has mixed sugars in) that is going to stay behind. In essence, both examples have the same, constant amount of sugar available. You are producing 8.5 gallons of pre-boil wort (1g is left behind as deadspace) in the second example and 7.5 gallons in the first. Surely the OG's would be different?
With a constant amount of sugar that presumably dissolves evenly, it doesn't seem possible that the OG's would be the same. If it were, then it would mean you could (theoretically) have a tun with 10 gallons of deadspace and the OG wouldn't change?
To illustrate another way. With the deadspace at 0 gallons, we are dissolving the sugars from 12 lbs of malt into ~8.92 gallons of water. With the deadspace at 1 gallon, we are dissolving the sugars from 12 lbs of malt into ~9.92 gallons of water. Why would BeerSmith calculate the OG as the same in both situations?