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- Thread starter gregsky
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There is 28.35 g in one oz (weight), so if you want 4 oz then you would want 113.4 g. (4 oz x 28.35 = 113.4 g.)

According to wikpedia, dextrose/glucose weighs 1.54 g cm³.

There's 29.57 cm³ per oz. (volume) so to if you multiply 1.54 g x 29.57 you get 45.54. This means that dextrose weighs 45.54 g. per oz (volume).

Therefor, if you want 4 oz (weight) which equals 113.4 g. then you would divide your (desired amount of dextrose in g.) by the (weight in g. per oz. in volume) to find how many oz (volume) of dextrose to use. (113.4 / 45.54 = 2.49 oz. (volume))

8 oz. (volume) per cup means that 2.49 oz. = 0.311 cups which is about 1/3 C. of dextrose = 4 oz (weight)

Or 141.75 / 45.54 = 3.112 oz. (volume) = 0.389 cups dextrose = 5 oz (weight).

I don't know what size batch you're doing, but you usually use 3/4 C dextrose for a 5 gal. batch. So one of three things is happening here. 1. I messed up on my math, 2. You're doing a 2.5 - 3 gal. batch, or 3. 4-5 oz. dextrose isn't enough priming sugar.

Hope this helps ya out.

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5 oz is about 3/4 Cup...

So my math or sources must be messed up somewhere on my previous post.

Ironically, that also means that 3/4 cup of one form of dextrose won't be the same as 3/4 cup of another. I've seen some that's almost as course as table sugar, and some that's more like powered sugar.

A scale is one of those really handy things in brewing, you might want to spend $20 or so and get a half decent one.

bradsul said:

A scale is one of those really handy things in brewing, you might want to spend $20 or so and get a half decent one.

+1!

TL

Cheers

BeerCanuck

Jesse17 said:Here's your google welfare check...

There is 28.35 g in one oz (weight), so if you want 4 oz then you would want 113.4 g. (4 oz x 28.35 = 113.4 g.)

According to wikpedia, dextrose/glucose weighs 1.54 g cm³.

There's 29.57 cm³ per oz. (volume) so to if you multiply 1.54 g x 29.57 you get 45.54. This means that dextrose weighs 45.54 g. per oz (volume).

Therefor, if you want 4 oz (weight) which equals 113.4 g. then you would divide your (desired amount of dextrose in g.) by the (weight in g. per oz. in volume) to find how many oz (volume) of dextrose to use. (113.4 / 45.54 = 2.49 oz. (volume))

8 oz. (volume) per cup means that 2.49 oz. = 0.311 cups which is about 1/3 C. of dextrose = 4 oz (weight)

Or 141.75 / 45.54 = 3.112 oz. (volume) = 0.389 cups dextrose = 5 oz (weight).

I don't know what size batch you're doing, but you usually use 3/4 C dextrose for a 5 gal. batch. So one of three things is happening here. 1. I messed up on my math, 2. You're doing a 2.5 - 3 gal. batch, or 3. 4-5 oz. dextrose isn't enough priming sugar.

Hope this helps ya out.

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You're right Brad. I wasn't taking into account that some people compact when measuring...I'm not a compacter...bradsul said:

A scale is one of those really handy things in brewing, you might want to spend $20 or so and get a half decent one.

What's that emotion/smiley suppose to mean?GaryA said:

I quoted it just to see what the html discription would be, but it just says "434_crazy_eyes.gif" So I'm still confused.

Or you could get more precise, transfer your dextrose to an airtight canister, and fill the empty bag with something non-compressible (water, if the bag is plastic), and measure that. (rho) = (80oz)/(water volume).

It's way more trouble than buying a scale, though...

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Would we then need to factor for moisture weight? Runs for the hills........

you guys crack me up! Thanks

" ??? " !!!!!! . funny thread {how much does thread of sugar weigh}

1.56 g/cm³

so use the wundows calc, powder it, an every cm3 will weight 1.56g's...

so use the wundows calc, powder it, an every cm3 will weight 1.56g's...

hmmm, what kind of bottles, and how do you cap them?

12 oz bottles with 4 or 5 pint bottles. I have a few manual cappers I use.

https://www.homebrewtalk.com/threads/bottle-cap-size.723726/12 oz bottles with 4 or 5 pint bottles. I have a few manual cappers I use.

i'm not sure, but maybe of use to you....

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