I am attempting my first multi-step mash, and I have a question regarding the grain/water mash ratio.
The recipe I am following indicates:
"Step mash, with rests at 113F and 153F. Dilution of 2 quarts per pound. Mash out at 170F."
My assumption is that the instructions are for a temperature step mash, where the dilution is 2 quarts per pound, and the temperature is increased from 113 to 153 via an external heat source.
I am performing an infusion step mash.
Should my dilution be 2 quarts per pound for both the 113F rest as well as the 153F rest (4 quarts per pound total)? Or should my dilution be 1 qt per lb for the 113 rest, and 1 qt per lb for the 153 rest (2 qt/lb total)? I am leaning towards the latter.
Bonus question. Is there a specific dilution I should use for the mash-out, or should I simply use enough almost-boiling water to bring the mash temperature up to 170F?
Thanks in advance.
The recipe I am following indicates:
"Step mash, with rests at 113F and 153F. Dilution of 2 quarts per pound. Mash out at 170F."
My assumption is that the instructions are for a temperature step mash, where the dilution is 2 quarts per pound, and the temperature is increased from 113 to 153 via an external heat source.
I am performing an infusion step mash.
Should my dilution be 2 quarts per pound for both the 113F rest as well as the 153F rest (4 quarts per pound total)? Or should my dilution be 1 qt per lb for the 113 rest, and 1 qt per lb for the 153 rest (2 qt/lb total)? I am leaning towards the latter.
Bonus question. Is there a specific dilution I should use for the mash-out, or should I simply use enough almost-boiling water to bring the mash temperature up to 170F?
Thanks in advance.