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Utilization Equation question

Discussion in 'Beginners Beer Brewing Forum' started by richwyso, Dec 29, 2012.

 

  1. #1
    richwyso

    Active Member

    Posted Dec 29, 2012
    I have been reading this book from how to brew from john palmer and i wonder if anyone out there is familiar with the equation below. More specifically, its been driving me crazy all morning trying to figure out where the 7/10 came from. Does anyone know? I have posted below the quote from the book:

    For example, to calculate the utilization for a boil gravity of 1.057 at 30 minutes, look at the utilization values for 1.050 and 1.060. These are .177 and .162, respectively. There is a difference of 15 between the two, and 7/10ths of the difference is about 11, so the adjusted utilization for 1.057 would be .177 - .011 = 0.166.

    dont know where the 7/10 came from. thanks
     
  2. #2
    esahc161

    Member

    Posted Apr 23, 2014
    I have this exact same question...bump?
     
  3. #3
    Kingbogart

    Well-Known Member

    Posted Apr 23, 2014
    There are 10 points between 1.050 and 1.060. You are at 1.057, which is 7/10 of those points. The difference between 1.050 and 1.060 is 15, 7/10*15 = 11.
     
    mrgbu likes this.
  4. #4
    freisste

    Well-Known Member

    Posted Apr 23, 2014

    +1. Interpolation.
     
  5. #5
    mrgbu

    Member

    Posted Jul 2, 2014
    omg thank you I was stuck and confused on this even reread the chapter to make sure I didn't miss anything :drunk:
     
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