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Old 02-18-2013, 06:39 PM   #1
Bevilaquafoto
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I have been looking through the numerous threads regarding the use of a hydrometer, and, believe it or not, I am still confused. I brewed a graff and took an original gravity reading. It read 64. I think the correct way to read this is 1.064. I got a final gravity reading at the 8 mark, very close to the red line at the top of the hydrometer. Is this 1.08? Having gotten these two figures, both at 68 degrees, how do I go about using these two readings to determine alcohol content? Any help would be greatly appreciated.
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Old 02-18-2013, 06:45 PM   #2
Jayhem
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Yes, 64 is actually 1.064.

The formula for determining alcohol content (ABV%) is

(OG - FG) x 131.25

So if your OG (Original Gravity) was 1.064 and FG (Final Gravity) was 1.012 you would have...

(1.064 - 1.012) x 131.25 = 6.8%
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Old 02-18-2013, 06:46 PM   #3
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It's probably 1.008.
(OG-FG)*131.25 = ABV
(1.064-1.008)*131.25= 7.35
so 7.4%abv

 
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Old 02-18-2013, 06:56 PM   #4
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Great! Thank you. Does this make any sense?

1.064 OG minus

1.008 FG = .056

.056 x 131.25 = 7.35 ABV

Does that look about right?
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Old 02-18-2013, 06:56 PM   #5
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Quote:
Originally Posted by Bevilaquafoto View Post
Great! Thank you. Does this make any sense?

1.064 OG minus

1.008 FG = .056

.056 x 131.25 = 7.35 ABV

Does that look about right?
You got it!
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Old 02-18-2013, 07:02 PM   #6
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Thank you! I'm very happy. I have to get a hydrometer that's a bit easier to read, but I am very happy to finally know how. Thanks again everyone.
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Old 02-19-2013, 10:04 AM   #7
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Quote:
Originally Posted by Bevilaquafoto View Post
Thank you! I'm very happy. I have to get a hydrometer that's a bit easier to read, but I am very happy to finally know how. Thanks again everyone.
there's an app for that (abv)

 
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Old 02-19-2013, 10:29 AM   #8
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Quote:
Originally Posted by Bevilaquafoto View Post
Great! Thank you. Does this make any sense?

1.064 OG minus

1.008 FG = .056

.056 x 131.25 = 7.35 ABV

Does that look about right?
And by the way,it isn't expressed as ".056". You don't drop the one,so it's "1.056". Water at 66F being "1.000" you're adding the number to it that's over the gravity of water when you express it.
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Old 02-19-2013, 12:10 PM   #9
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Quote:
Originally Posted by unionrdr View Post
And by the way,it isn't expressed as ".056". You don't drop the one,so it's "1.056". Water at 66F being "1.000" you're adding the number to it that's over the gravity of water when you express it.
The .056 is correct.It is the difference betweed OG(1.064) and FG(1.008) 1.064-1.008=.056

.056x131.25=7.35a=ABV

 
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