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Old 02-01-2013, 09:56 PM   #1
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Default explain efficiency please?

The recipe I did last night said it would make 5 gallons at 75% efficiency. How can I tell what my efficiency was? I think it has to do with my OG, right? Mine was 1.057 at 70 degrees, which would make it 1.058 after adjustment for temp. How do I know what my efficiency was?


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Old 02-01-2013, 09:59 PM   #2
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It has to do with the amount of grain you mash and what OG you ended up with.

Here is a way to calculate it. Just put in your ingredients and the gravity and it will five you your efficiency.

http://www.brewersfriend.com/brewhouse-efficiency/


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Old 02-01-2013, 10:02 PM   #3
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It is a measure of the percentage of the total possible sugar you get out of your grain. E.g., if the total potential for your grain bill is an OG of 1.050 and you end up with 1.040, your efficiency was 80%. I think I did that math right.
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Old 02-02-2013, 12:07 AM   #4
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In order to calculate efficiency you need a list of grains (and their weight), the original gravity measured and the exactly volume measurement of wort you had when that OG measurement was made.
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Old 02-02-2013, 07:43 AM   #5
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Quote:
Originally Posted by beergolf View Post
It has to do with the amount of grain you mash and what OG you ended up with.

Here is a way to calculate it. Just put in your ingredients and the gravity and it will five you your efficiency.

http://www.brewersfriend.com/brewhouse-efficiency/
Yup, that's the one I use.


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