I'm trying to figure this out for myself and learn to use Plato and Brix, as the gravity/points scale uses very nonintuitive units IMO. Wherever I'm wrong point it out, only way I'm going to learn.
Quote:
Originally Posted by ajdelange
53*473.18/60 = 427.98 grams is sugar. Thus the rest, 625.40  427.98 = 207.42 grams must be water.

53*473.18/60=417.98, though I suspect this is a typo/misreading as 625.4417.98=207.42
Quote:
You started with 18.17 L of wort at SG 1.080 corresponding to 19.33 °P so its weight was .1933*18.17*1.080*.998203 = 3.786 kg

18L of wort can't possibly only weigh 3.8 kg. I don't know what .998203 is from but I'm guessing a constant of some sort, but either way it is such a small multiplier that I'm ignoring it in my estimate until I actually know. Just volume*density for total weight, right? 18.17 * 1.080 = 19.624 kg
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of which .1933*3786= 731.83 grams was sugar

.1933*19624 = 3793g sugar (guessing this is the 3.786 kg you reached above)
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and the rest, 3786731.83 = 3054 grams was water.

19624  3793 = 15831 g water
total sugar = 4211
total water = 16038 + 300 ml dissolved syrup into = 16338
4211/(16338+4211)=20.5*P ~1.085 SG
Confirmation with sloppy points scale:
4.8 g of 1.080 wort = 384 points
418 g sucrose ~= .92 lbs ~= 40.5 points
424.5 points
new volume = 4.8 gals + 800 ml (seems really high to me also) = 5.1 gals
424.5/5.1 = 1.083
EDITcatching my own math error here, and reading error, should be
new volume = 4.8 gals + 850 ml (seems really high to me also) = 5.02 gals
424.5/5.02 = .846, so 1.0846 SG, much closer than before
The numbers are farther apart than I'd like but in the same basic area, and that .998 multiplier I ignored might bring them closer together.