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Old 12-29-2012, 05:58 PM   #1
richwyso
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Default Utilization Equation question

I have been reading this book from how to brew from john palmer and i wonder if anyone out there is familiar with the equation below. More specifically, its been driving me crazy all morning trying to figure out where the 7/10 came from. Does anyone know? I have posted below the quote from the book:

For example, to calculate the utilization for a boil gravity of 1.057 at 30 minutes, look at the utilization values for 1.050 and 1.060. These are .177 and .162, respectively. There is a difference of 15 between the two, and 7/10ths of the difference is about 11, so the adjusted utilization for 1.057 would be .177 - .011 = 0.166.

dont know where the 7/10 came from. thank


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Old 12-29-2012, 07:35 PM   #2
ajdelange
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He is interpolating. The densities of worts are quite close to being linearly dependent on the 'points' obtained by subtracting 1 from the specific gravity and multiplying by 1000. Thus a wort of SG = 1.050 has a density proportional to 50 points, one at 1.060 a density proportional to 60 points and one at 1.057 a density proportional to 57 points. Fifty seven (57) lies 7/10 of the way between 50 and 60 so we suppose that the density of 1.057 wort is equal to the density of 1.050 wort plus 0.7 times the difference between the density of 1.060 and 1.050 worts. The formula assumes the utilization is also linear with density so that the utilization for a 1.057 wort will be the utilization for a 1.050 wort plus 0.7 times the difference between the utilization at 1.060 and that at 1.050.
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Old 12-31-2012, 03:07 PM   #3
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Thanks so much for that clarification.. that makes a lot more sense now.. You are da bomb!
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