Originally Posted by outstretched
I get roughly .458% acidity with my calculations. Not sure if they are right though. Here is what I did:
First I found the concentration of each liquid (84% to 16%) then I multiplied 1.3 by .16 = .208 then you add the base acidity level of .25 to .208 and get .458%.
The ratio was the insight I was looking for. Using your logic I think one would multiply .25 X .84 to get the level of the base. Then it would be (1.3 X .16) + (.25 X .84) = .418
Thanks also Leadgolem for the points of acid technique. Both of these lead to similar answers.
I was concerned that if I added all the crab I would overshoot my acid target and it seems like I will not, as I was aiming for the range of .4 to .5