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Old 11-09-2011, 03:59 PM   #1
jmf143
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Is there a "quick and dirty" method of determining the amount of lactic acid 88% to use to drop sparge water pH by a constant amount i.e. "1 ml of lactic acid in 1 gallon of sparge water will reduce pH by X units"?
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Old 11-09-2011, 05:15 PM   #2
ajdelange
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The amount required depends on the original pH and alkalinity of the water and the pH you want to shift it to. Bru'n water has a calculator.

 
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Old 11-10-2011, 08:27 PM   #3
jmf143
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Quote:
Originally Posted by ajdelange View Post
The amount required depends on the original pH and alkalinity of the water and the pH you want to shift it to. Bru'n water has a calculator.
I am aware of this but could have worded my question better. Assume that my tap water pH is 8.1, I'm aiming for a sparge pH of 5.7 and I want to sparge with 6 gallons. Bru'n Water will calculate for the sake of argument 3 ml of lactic acid for me. Can I assume I can always add .5 ml of lactic acid per gallon of sparge water regardless of the grain bill, batch size etc. since 3 ml / 6 gallons = .5 ml lactic acid per gallon of sparge water?
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Old 11-10-2011, 09:01 PM   #4
remilard
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Quote:
Originally Posted by jmf143 View Post
I am aware of this but could have worded my question better. Assume that my tap water pH is 8.1, I'm aiming for a sparge pH of 5.7 and I want to sparge with 6 gallons. Bru'n Water will calculate for the sake of argument 3 ml of lactic acid for me. Can I assume I can always add .5 ml of lactic acid per gallon of sparge water regardless of the grain bill, batch size etc. since 3 ml / 6 gallons = .5 ml lactic acid per gallon of sparge water?
Assuming the same water composition and target pH, yes, the amount of acid required is a linear function of the amount of water treated.

 
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