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Old 10-25-2011, 05:31 PM   #1
Bsquared
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So the last part of my Electric set up I need is the E-Stop. I ordered the big red mushroom, and have an in-line fuse holder for the 1amp fuse, but I am a little stumped on the two 1Ω resistors. The resistors I am picturing are the ones that get soldered in to a board. are these the ones people use? How are these incorporated with a wire? are they just soldered in-line to the wire? or is there a better way.

Thanks in advance for the help.

 
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Old 10-25-2011, 06:01 PM   #2
samc
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Are you talking about the P-J device? If so I just carefully, soldered a wire on the metal leads.

 
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Old 10-25-2011, 06:19 PM   #3
audger
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anything that gives you a little resistance will work. for only 1ohm, you can probably even get away without it- though i wont tell you to do that without seeing the whole wiring diagram. i believe all its for is to trickle a little current to the ground wire to trip the GFCI. a standard 1/8th watt resistor with some 28 or 26ga wire will work for that.

do you have a specific wiring diagram to confirm?

 
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Old 10-25-2011, 06:58 PM   #4
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Yes I'm using PJ wire diagram for the e-stop. This is what I am thinking of...
Is this right?

 
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Old 10-25-2011, 11:39 PM   #5
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On his diagrams they are 1K ohm 1W.

 
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Old 10-26-2011, 02:51 AM   #6
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Yes, you need something like this... these are 1 watt resistors



I think the ones in post #4 or 1/8, 1/4, and 1/2 watt

I picked up from my local electronics surplus place...
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Old 10-26-2011, 02:55 AM   #7
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Sweet,Thanks. I did not see the 1K 1W this morning. I have a good electronic component shop I go to down the street. I'm sure they will have them.

 
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Old 10-26-2011, 03:08 AM   #8
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If you get stuck, i can get some more and send some to you.
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Black Pug Brewing - Progress Thread

In the fermenter: Pugkin Ale, Apfelwein
In the keezer: Black Pug Coconut Porter, Black Pug Wheat, Black Pug IPA
Gone: Black Pug Blonde Ale

 
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Old 10-26-2011, 03:16 AM   #9
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Using two 1k resistors results in 7 Watts dissipated and 60mA of fault current. I assume the wattage of the resistors doesn't matter much as the Gfi should trip before the resistors have much chance to heat.

I think the fault current could be reduced by raising the resistance and maybe splitting the load into three resistors. Then the wattage rating of the resistors would not be exceeded. Is this worth doing? Wouldn't 15 or 20mA be sufficient to trip the gfi? I think this is a brilliant way to provide an e stop but I never really understood the excessive current or undersized resistors.

 
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Old 10-26-2011, 03:48 AM   #10
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Please keep in mind that once the E-Stop is pressed the GFCI will cut all of the power to the control panel within a millisecond. There is no need to have higher wattage resistors or resistors that limit the current draw to a lower level. We are talking about 0.06A for less time that it would take for you to blink your eye. Will the resistors heat up? NOT a chance.!

 
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